posted by suzy .
right triangle ABC with right angle C, AC=22 and BC=6, altitude CD where D is on hypotenuse AB. What is the ratio of the area of triangle ADC to the area of triangle CDB? Write ratio as n:1 and round n to the nearest hundredth.
Mark you similar triangles filling in all given information
triangle ADC similar to
The ratio of areas of two triangles is equal to the squares on their corresponding sides.
Triangle ADC : triangle CDB = (CA)^2 : (BC)^2
= 22^2 : 6^2
= 484 : 36
= 121 : 9
or (121/9) : 1
n = 121/9 or 13 4/9 or 13.44444.....