Pharmaceutical Dosage Forms

posted by .

If there is 1 g KH2PO4 and 1 g K2HPO4 in 100mL of solution, what is the mEq/mL of potassium? The Answer is 0.19mEq/mL. But I need to show work on how to get the answer.

Textbook Applied physical pharmacy By Mansoor M. Amiji, Beverly J. Sandmann
Chapter 3

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. chemistry

    Given: [SO4^2-] in a 0.2M NA2SO4 solution How do I express this in meq/l?
  2. Statistics

    I need help on this one too. Any one willing to get me started?
  3. Chemistry

    You need to prepare 1.000 L (in a volumetric flask) of 0.50 M phosphate buffer, pH 6.77. Use the Henderson Hasselbalch equation with a value of 6.64 for pK2 to calculate the quantities of K2HPO4 and KH2PO4 you need to add to the flask. …
  4. Chemistry

    As a technician in a large pharmaceutical research firm, you need to produce 400. mL of 1.00 M potassium phosphate solution of pH = 7.18. The pKa of H2PO4- is 7.21. You have 2.00 L of 1.00 M KH2PO4 solution and 1.50 L of 1.00 M K2HPO4 …
  5. chemistry

    As a technician in a large pharmaceutical research firm, you need to produce 200.mL of 1.00 M a phosphate buffer solution of pH = 7.19. The pKa of H2PO4− is 7.21. You have 2.00 L of 1.00 M KH2PO4 solution and 1.50 L of 1.00 M …
  6. Chemistry

    As a technician in a large pharmaceutical research firm, you need to produce 100.mL of 1.00 M a phosphate buffer solution of pH = 7.45. The pKa of H2PO4− is 7.21. You have 2.00 L of 1.00 M KH2PO4 solution and 1.50 L of 1.00 M …
  7. Chemistry

    a solution made by dissolving 2.733g KH2PO4 and 4.508g K2HPO4 in water to give 250 ml of solution. is the answer... 7.432= ph
  8. Analytical Chemistry

    This question pertaining to buffer systems! How would you prepare 10.0mL of 0.0100M phosphate buffer, pH = 7.4 0, from stock solution of 0.100M KH2PO4 and 0.250M K2HPO4, pKa of KH2PO4 is 7.20. Please help me in figuring out how I even …
  9. CHEMISTRY

    As a technician in a large pharmaceutical research firm, you need to produce 450. mL of 1.00 M a phosphate buffer solution of pH = 7.20. The pKa of H2PO4− is 7.21. You have 2.00 L of 1.00 M KH2PO4 solution and 1.50 L of 1.00 …
  10. Biochem

    Using stocks of 0.1 M KH2PO4 and 0.1 M K2HPO4 how much 0.1 M K2HPO4 is needed to prepare 20 mL of a buffer solution at pH 7.2. The pKa of phosphate is 6.82. I know to solve for the ratio using henderson hasselbach but im lots after …

More Similar Questions