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The numbers 1-10 are placed on cards, and the cards are put in a hat. If two cards are drawn, in order, without replacement, what is the probability that one number is even and the other a prime?

I know there are 4 primes-2,3,5,7 and 5 even numbers 2,4,6,8,10

not sure how to figure the probability

  • math -

    It could be
    PE or EP

    what messes things up is that the 2 is in both groups
    PE:
    case 1: the 2 was picked as the prime
    prob of that is (1/10)(4/9)
    case 2: the 2 was not picked as the prime
    prob of that is (3/10)(5/9)

    so prob (PE) = 4/90 + 15/90 = 19/90

    EP:
    case 1: the 2 was picked as the even
    prob = (1/10)(3/9) = 3/90
    case 2: the 2 was not picked as the even
    prob = (4/10)(4/9) = 16/90
    prob(EP) = 3/90 + 16/90 = 19/90

    so prob of (one prime and one even) = 19/90 + 19/90 = 19/45

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