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What is the angular momentum of a 2.7 kg uniform cylindrical grinding wheel of radius 12 cm when rotating at 1600 rpm? How much torque is required to stop it in 4.4 s?


    The angular momenturm is I*w, where
    I = (1/2) M R^2
    and w is the angular veocity.

    The required torque*time to stop rotation is I*w. Therefore
    (Torque to stop) = (I*w)/(time)

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