calculus
posted by dee .
Suppose a scooter travels at a velocity of v(t)= 8t meters/hour. Then the TOTAL distance traveled by the scooter over the first 2 hours is?

so distance = 4t^2 + c
when t=0, d=0, (hasn't gone anywhere yet)
so c=0
distance = 4t^2
so in 2 hours
distance = 4(2^2) = 16 m
(silly question, how can the speed keep increasing?
And it took 2 hours to go 16 m?