# calculus

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Suppose a scooter travels at a velocity of v(t)= 8t meters/hour. Then the TOTAL distance traveled by the scooter over the first 2 hours is?

• calculus -

so distance = 4t^2 + c
when t=0, d=0, (hasn't gone anywhere yet)
so c=0
distance = 4t^2

so in 2 hours
distance = 4(2^2) = 16 m

(silly question, how can the speed keep increasing?
And it took 2 hours to go 16 m?

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