Algebra/equations

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Write an equation of the the line containing the given point and perpendicular to the given line. (7,-5); 9x+7y = 3.

What I have so far. y-9=(1/9(x-3). Not sure after this.

  • Algebra/equations -

    First of all the new slope should have been 7/9.
    Now you have to use the given point this way ...
    y + 5 = (7/9)(x-7)
    multiply each side by 9 (I don't like fractions in my equations)
    9y + 45 = 7x - 49
    -7x + 9y = -93
    7x - 9y = 93

    A quick way to do the above..
    If Ax + By = C is the equation , then
    the line Bx - Ay = K is perpendicular to it,
    so
    if 9x + 7y = 3 is given , then
    7x - 9y = k is the perpendicular line
    sub in the given point ...
    7(7) - 9(-9) = c = 93

    7x - 9y = 93 is your new line

  • Algebra/equations -

    thank u

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