Algebra/equations
posted by AMY .
Write an equation of the the line containing the given point and perpendicular to the given line. (7,5); 9x+7y = 3.
What I have so far. y9=(1/9(x3). Not sure after this.

First of all the new slope should have been 7/9.
Now you have to use the given point this way ...
y + 5 = (7/9)(x7)
multiply each side by 9 (I don't like fractions in my equations)
9y + 45 = 7x  49
7x + 9y = 93
7x  9y = 93
A quick way to do the above..
If Ax + By = C is the equation , then
the line Bx  Ay = K is perpendicular to it,
so
if 9x + 7y = 3 is given , then
7x  9y = k is the perpendicular line
sub in the given point ...
7(7)  9(9) = c = 93
7x  9y = 93 is your new line 
thank u
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