Calculus  please help!
posted by K .
Suppose that 0 < c < ¥ð/2. For what value of c is the area of the region enclosed by the curves y = cos x, y = cos(x  c), and x = 0 equal to the area of the region enclosed by the curves y = cos(x  c), x = ¥ð, and y = 0?
i have no idea how to solve this question.

Please confirm if ¥ð stands for π.
Also, please check the limits of integration. The bottom limit seems to be missing for the first area, and confirm if the right limit for the second area is indeed π or should it be π/2. 
yes, ¥ðstands for pi. The quesiton that i wrote above is all information that are given. There is no other limit on this integration. I will wrote the question once again. Please help. Thank You.
Suppose that 0 < c < pi/2. For what value of c is the area of the region enclosed by the curves y = cos x, y = cos(x  c), and x = 0 equal to the area of the region enclosed by the curves y = cos(x  c), x = pi, and y = 0?
Respond to this Question
Similar Questions

calculus
find the value of m so that the line y = mx divides the region enclosed by y = 2xx^2 and the xaxis into two regions with equal area i know that the area enclosed by y=2xx^2 is 4/3 so half of that would be 2/3 however, i have no … 
Calculus  MathMate Please help
I asked this question on last thursday and u told me that the bottom limit for the 1st and the right limit for the 2nd area is missing? 
Calculus  MathMate Please help
ok, i tried to do what you told me but i cant solve it for c because they cancel each others out! the integral for the first one i got is [sin(c)cos(x)cos(c)sin(x)+sin(x)+c] and the integral for the 2nd one i got is [sin(c)cos(x)+cos(c)sin(x)sin(x)+c] … 
Calculus (Area Between Curves)
Find the area of the region IN THE FIRST QUADRANT (upper right quadrant) bounded by the curves y=sin(x)cos(x)^2, y=2xcos(x^2) and y=44x. You get: a.)1.8467 b.) 0.16165 c.) 0.36974 d.) 1.7281 e.) 0.37859 
Calculus (Definite Integrals)
How many definite integrals would be required to represent the area of the region enclosed by the curves y=(cos^2(x))(sin(x)) and y=0.03x^2, assuming you could not use the absolute value function? 
CalculusArea between curves
Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y. Then find the area of the region. 2y=4*sqrt(x) , y=5 and 2y+4x=8 please help! i've been trying this problem the last couple days, even … 
Calculus Area between curves
Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y. Then find the area of the region. 3y+x=3 , y^2x=1 
CALCULUS
Sketch the region enclosed by the given curves. y = 4/X y = 16x, y = 1X/16 x > 0 and the area between the curves 
math
Roughly sketch the region enclosed by the curves y = sin x, y = cos x and the x  axis between x = 0 and x = p/ 2 . Also find the area of this region. 
Calculus
find the area of the region bounded by the curves y=x^21 and y =cos(x)