posted by kay
X rays of wavelength 2.63 were used to analyze a crystal. The angle of first-order diffraction (n = 1 in the Bragg equation) was 16.14°.
What is the spacing between crystal planes?(in pm)
Do I just plug everything in the Bragg's equation?
I remember Bragg's equation being
n*lambda = 2d*sin theta.
oh that's right!
I still have a problem. I'm still getting the wrong answer
and the answer is suppose to be 479 pm
I think you punched in a wrong number somewhere. I get 473 something.