# Chemistry

posted by kay

X rays of wavelength 2.63 were used to analyze a crystal. The angle of first-order diffraction (n = 1 in the Bragg equation) was 16.14°.
What is the spacing between crystal planes?(in pm)

Do I just plug everything in the Bragg's equation?

nλ=d*sinθ
n=1 ?
λ=263 pm?

1. DrBob222

I remember Bragg's equation being
n*lambda = 2d*sin theta.

2. kay

oh that's right!

I still have a problem. I'm still getting the wrong answer

nλ=2d*sinθ
(1)*(263)/(2*sin(16.14))=d
-571.8=d

and the answer is suppose to be 479 pm

3. DrBob222

I think you punched in a wrong number somewhere. I get 473 something.

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