Chemistry
posted by Anonymous .
A 19.6 g sample of ice at 10.0°C is mixed with 100.0 g of water at 75.4°C. Calculate the final temperature of the mixture assuming no heat loss to the surroundings. The heat capacities of H2O(s) and H2O(l) are 2.08 and 4.18 J g1 °C1, respectively, and the enthalpy of fusion for ice is 6.02 kJ/mol.

qice=qliq
q=delta H ice * n
q=S(liq)*Mass(liq)*(TfTi)?
Help please!
I try setting the two equal to each other and plug in the numbers but I still get it wrong.
(6020 J/mol)*(19.6g)*(1mol/18g)=(4.18 J g1 C1)(100g)(Tf75.4)