posted by sandhu
A firetruck is traveling at a velocity of +20 m/s in the x direction. As the truck passes x=63m it shoots a tennis ball backwards with a speed of 20 m/s relative to the truck at an angle of 39° from a height of 1.4 m. Neglect air resistance. At what x value does the tennis ball hit the ground?
Write equations for x and y vs time after the x=63 m point is passed. Solve for the time when y = 0.
Apply that time to the x(t) equation to get the x location where it hits the ground.