Calculus 1 Implicit differentiation

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Help please help me understand what i am doing wrong in this problem! x^3+3x^2y+y^3=8 find dy/dx using implict differentiation. The answer is x^2+2xy
-------- but i keep getting x^2y
x^2+y^2 -----
x^2+y^2

  • Calculus 1 Implicit differentiation -

    x^3+3x^2y+y^3=8

    3x^2 + 3x^2 dy/dx + y(6x) + 3y^2 dy/dx = 0
    dy/dx(3x^2 + 3y^2) = -3x^2 - 6xy
    dy/dx = -3x(x + 2y)/(3(x^2 + y^2)
    = -x(x+2y)/(x^2 + y^2)
    or
    = -(x^2 + 2xy)/(x2 + y^2)

    I don't understand the answer the way you typed it, but there should definitely be a negative in there.

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