Math
posted by Nina .
A 384m wire is cut into three pieces. The second piece is 3 m longer than the first. The third is fourfifths as long as the first. How long is each piece?

first > x
second > x+3
third > (4/5)x
solve x + x+3 + (4/5)x = 384
I suggest multiplying each term by 5, then it becomes real easy. 
Flenght of first size
Slenght of second size
Tlenght of third size
S=F+3
T=(4/5)*F
F+S+T=F+F+3+(4/5)F=384
2F+3+(4/5)F=384
2F+(4/5)F=3843
2F+(4/5)F=381 Multiply with 5
10F+4F=381*5
14F=1905 Divide with 14
F=1905/14
S=F+3=(1905/14)+(42/14)
Becouse (42/14)=3
S=1947/14
T=(4/5)*F=(4/5)*(1905/14)
=(4/5)*[(3*5*127)/14]
Becouse 1905=3*5*127
T=(4*3*127)/(14)=1524/14
T=1524/14
F+S+T=(1905/14)+(1947/14)+(1524/14)
=5376/14=384 
Pooo