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algebra word problems

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you have 95 coins that total $10.75. the coins consist of only quarters and nickels. how many of each coin do you have?

  • algebra word problems -

    .25q+.05n=10.75 (1)
    q+n=95 (2)
    Multiply (2) by -.25 to cancel the q's
    .25q+.05n=10.75 (1)
    -.25q-.25n=-23.75 (3)
    -.2n=-13
    Divide both sides by -.2
    n=65
    From (2), q+n=95, q+65=95, q=30
    When plugged back into equation 1, it checks. It works in both equations, so this is your solution.

  • algebra word problems -

    You have a total of $175 in $5 and $20 bills. The number of $5 bills you have is 3 more than 4 times the number of $20 bills. How many of each type of bill do you have?

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