# algebra word problems

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you have 95 coins that total \$10.75. the coins consist of only quarters and nickels. how many of each coin do you have?

• algebra word problems -

.25q+.05n=10.75 (1)
q+n=95 (2)
Multiply (2) by -.25 to cancel the q's
.25q+.05n=10.75 (1)
-.25q-.25n=-23.75 (3)
-.2n=-13
Divide both sides by -.2
n=65
From (2), q+n=95, q+65=95, q=30
When plugged back into equation 1, it checks. It works in both equations, so this is your solution.

• algebra word problems -

You have a total of \$175 in \$5 and \$20 bills. The number of \$5 bills you have is 3 more than 4 times the number of \$20 bills. How many of each type of bill do you have?

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