# graphing linear equatios

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I am really confused...can someone help me with this? I am supposed to graph solution of given system of linear inequality:

y is greater than 4x-3
y is less than or equal to x+2

• graphing linear equatios -

Hopefully some of these tutorials will help you:

http://search.yahoo.com/search?fr=mcafee&p=graphing+linear+inequality+tutorials

Sra

• graphing linear equatios -

Consider the "equation" of the corresponding function, I will use yours as an example

y = 4x-3
Since it is a straight line, all you need are two points

y > 4x - 3, draw a dotted line to show that the points are excluded.
Shade in the region above that line
If the relation had been
y < 4x-3 , you would shade in the region below the line

If the relation had been ≥ or ≤ , you would make the boundary line solid, to show the points on the line would be included.

my explanation applies to all inequations of the form
y > f(x), y < f(x), y ≥ f(x), or y ≤ f(x)

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