How much heat is required to melt 43.5g of ice at its melting point?
To find out how much heat is required to melt a given amount of ice, you need to use the heat of fusion for ice. The heat of fusion is the amount of heat energy required to change a substance from a solid to a liquid without changing its temperature.
The heat of fusion for ice is 334 J/g. This means that it takes 334 joules of heat energy to melt 1 gram of ice.
To calculate the heat required to melt 43.5 grams of ice, you can use the following formula:
Heat required = mass of ice * heat of fusion
Substituting the values:
Heat required = 43.5 g * 334 J/g
Now calculate the result:
Heat required = 14529 J
Therefore, to melt 43.5 grams of ice at its melting point, it would require 14529 joules of heat energy.