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How many mL of a 0.217 M aqueous solution of ammonium fluoride, NH4F, must be taken to obtain 3.63 grams of the salt?

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Start from calculating the molar mass of NH4F, F.

we need therefore, 3.63/F moles of ammonium fluoride.

The solution contains 0.217 M, or 0.217 moles in 1 litre.

which is 1000/0.217 ml mole^-1

hence volume required is

(1000/0.217 ml mole^-1)x (3.63/F moles )

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