mathalgebra
posted by peter .
how do i solve this using the substitution method
3x+2y=7
2x3y=4
x=72y/3
2(72y/3)3y=4
this is where i get stuck
help would be much apprieciated

3x+2y=7
3x=2y+7
x=2/3y+7/3
2(2/3y+7/3)3y=4
4/3y+14/33y=4
Combine like terms, solve for y, replace y in either original equation to solve for x. Post your work to get it checked.
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