9th grade

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a stone propelled from a catapult with a speed of 50m/s attains a height of 100m calculate the angle of projection

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    What is its initial vertical speed Vo ?
    v = Vo - 9.8 t
    v = 0 at top
    so
    t = Vo/9.8

    then height
    h = Vo t - (9.8/2) t^2
    100 = Vo^2/9.8 - (9.8/2) (Vo/9.8)^2

    100 = Vo^2/(2*9.8)
    Vo = 44.3 = speed sin theta
    sin theta = 44.3/50
    theta = 62.4 deg up from horizontal

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