Post a New Question


posted by .

The weight of corn chips dispensed into a 19-ounce bag by the dispensing machine has been identified as possessing a normal distribution with a mean of 19.5 ounces and a standard deviation of 0.1 ounce. Suppose 100 bags of chips are randomly selected. Find the probability that the mean weight of these 100 bags exceeds 19.6 ounces.
Choose one answer.

  • statistics -

    No answers given, but here is the process.

    Z = (mean1 - mean2)/standard error (SE) of difference between means

    SEdiff = √(SEmean1^2 + SEmean2^2)

    SEm = SD/√(n-1)

    Since only one SD is provided, you can use just that to determine SEdiff.

    Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion related to that Z score.

  • statistics -


Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question