MATH
posted by Kevin Loed .
The ratio of the perimeter of triangle KLM to the perimeter of triangle PQR is 5/3 and LM is 4 less than twice QR. Find LM and QR, if Triangle KLM~Triangle PQR.
Can someone solve this in ratio and proportion method? Thanks.

QR = X,
LM = (2X  4),
(2X  4) / X = 5/3,
Cross multiply:
6x  12 = 5x,
6x  5x = 12,
x = 12 = QR.
2X  4 = 2*12  4 = 20 = LM.