# MATH

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The ratio of the perimeter of triangle KLM to the perimeter of triangle PQR is 5/3 and LM is 4 less than twice QR. Find LM and QR, if Triangle KLM~Triangle PQR.

Can someone solve this in ratio and proportion method? Thanks.

• MATH -

QR = X,
LM = (2X - 4),

(2X - 4) / X = 5/3,
Cross multiply:
6x - 12 = 5x,
6x - 5x = 12,

x = 12 = QR.

2X - 4 = 2*12 - 4 = 20 = LM.

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