Math: Calculus
posted by REALLY NEED HELP!!!! .
Given f''(x) = 4x  3
and f'( 3) =2 and f( 3)=1.
Find f'(x) =______
and find f( 1) =_____

y '' = 4x+3
y' = 2x^2 + 3x + C
when x = 3, y' = 2
2 = 18  9 + C
C = 7
so y' = 2x^2 + 3x  7
then y = (2/3)x^3 + (3/2)x^2  7x + K
when x = 3, y = 1
take it from there by solving for K 
I don't know why but the answer is wrong.
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