A solution of alcohol and water is a% alcohol where a = 40. The solution is found to contain 32 milliliters of alcohol. How many milliliters total (both alcohol and water) are in the solution?
Let x = total volume.
32 = .4x
Solve for x.
To solve this problem, we need to first find the total volume of the solution.
We know that the solution is a% alcohol, where a = 40. This means that in every 100 milliliters of the solution, 40 milliliters are alcohol.
We are given that the solution contains 32 milliliters of alcohol. To find the total volume, we can set up a proportion using the information given:
40 milliliters of alcohol / 100 milliliters of solution = 32 milliliters of alcohol / x milliliters of solution
Cross-multiplying, we get:
40 * x = 32 * 100
Now we can solve for x:
40x = 3200
Dividing both sides by 40:
x = 3200 / 40
Simplifying, we get:
x = 80
Therefore, there are 80 milliliters of total solution (both alcohol and water) in the given solution.