posted by Quinn .
At 10 am two cars start traveling toward each other from 287 miles apart. They passed each other at 1:30 pm. If the rate of the fster car exceeded the rate of the slower car by 6 miles per hour, find the rat (in mph) of the faster car.
I think it is C, am I correct?
t = 3.5 hours
distance = rate * time
287 = r*t+(r+6)t = (2r+6)t =(2r+6)(3.5)
2r+6 = 287/3.5
solve for r and then answer with r+6