Math
posted by Samantha .
I'm really struggling with how to set this up:
A company has 18 members on its management team,10 men and 8 women. There is a conference in Hawaii, and the company decided to send 5 people. If the selection of five people is random, find the following probabilities.
I got the first three, but this one is hard.
d. If the supervisor of the team, one of the women, has to go what is the probability that there are two women and three men?
I tried doing something like 7C2*10C3/17C5
but didn't get the right answer. I'm so confused!

A company has 18 members on its management team,10 men and 8 women.
d. If the supervisor of the team, one of the women, has to go what is the probability that there are two women and three men?
If you take out the supervisor, you are left with 10 men and 7 women (17 in all), from which you need to choose 4 other people.
Total possible outcome = 17C4
Outcome for choosing one more woman and three men
= 7C1*10C3
Can you take it from here?
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