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Consider the equation 3x+5y=k, what values could k so that the x-intercept and y- intercept on the equations graph would both be integers. explain.

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Sra

3X + 5Y = K.

k = A * B = 3 * 5 = 15.
3 and 5 are now factors of 15.
Therefore, 15 is divisible by both:

3X + 5Y = 15,
Let X = 0,
3*0 + 5Y = 15,
5Y = 15,
Y = 3 = Y-Int.

Let Y = 0,
3X + 5*0 = 15,
3X = 15,
X = 5 = X-Int.

Graph: (0 , 3) , (5 , 0).

15!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!LOL IDK

It is 15=k math is fun and awesome!!!

15 is the answer and I have a question "if a is not equal to 0, find the intercepts of the graph of y=ax+b in terms of a and b?"

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