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Two cars travel the same distance. The first car travels at a rate of 37 mph and reaches its destination in t hours. The second car travels at a rate of 54 mph and reaches its destination in 3 hours earlier than the first car.
How long does it take for the first car to reach its destination?

Distance = rate * time

Let t = time for first car

37t = 54(t-3)

Solve for t.

37t = 54t-162
-17t = -162
t = 9.52941165

find an equation of variation where y varies directly as x,and y=7 when x= 3

Y varies directly as x,i.e x by y equal to 3 by 7

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