algebra

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two investments were made totaling $15,000. for a certain year these investments yielded $1432 in simple interest. part of the $15,000 was invested at 9% and part at 10%. find the amount invested at each rate.

a total of $1150 was invested, part of it at 12% and part at 11%. the total yield was $133.75. How much was invested at each rate?

  • algebra -

    first one:
    let the amount invested at 9% be x
    let the amount invested at 10% be 15000-x

    .09x + .10(15000-x) = 1432
    multiply each term by 100
    9x + 10(15000-x) = 143200
    -x = -6800
    x = 6800

    so $6800 were invested at 9% and $8200 at 10%

    do the second question the same way.

  • algebra -

    90+10(15000-x)=1432000

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