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Consider the following reaction.
CH4(g) + 2 O2(g) CO2(g) + 2 H2O(l) ÄH = -891 kJ
Calculate the enthalpy change for each of the following cases.
(a) 5.00 g methane is burned in excess oxygen.

  • chemistry -

    You omitted the arrow. We can't separate products from reactants without an arrow.

    -891 kJ x (5.00/16) = ?? kJ.

  • chemistry -

    5gCH4/16gCH4= 0.3125moles CH4
    Enthalpy change = 278kJ

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