physics

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the speed of a cyclist reduces uniformly from 2.5 m/s to 1.0 m/s in 12 s.
(a) calculate the deceleration of the cyclist.
(b) calculate the distance travelled by the cyclist in this time

  • physics -

    Sol
    Accelaration=F.V-I.V/TIME TAKEN
    NOW WE CAN SAY THAT,
    a=0-2.5/12
    a=-2.5/12
    a=0.2083

  • physics -

    a) Acceleration or deceleration = Final velocity - initial velocity / Time taken
    D = 1-2.5 / 12
    D= -0.125

    b) d = ½×(Vi + Vf) × t
    where
    d = displacement = ?
    Vf = final velocity = 1 m/s
    Vi = initial velocity = 2.5 m/s
    t = time = 12 s
    so
    d = ½×(2.5 + 1) × 12
    d = 21 m

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