Chemistry :(

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Given that:
2Al(s)+(3/2)O2(g)--->Al2O3(s)
change in H(rxn)= -1601 kJ/mol

2Fe(s)+(3/2)O2(g)--->Fe2O3(s)
change in H(rxn)= -821 kJ/mol


Calculate the standard enthalpy change for the following reaction:
2Al(s)+Fe2O3(s)--->2Fe(s)+Al2O3(s)


_______kJ

PLEASE EXPLAIN IM SOOO CONFUSED, CAN YOU SHOW ME THE STEPS?? Thank you

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