Respond to this Question
Similar Questions

calc
i did this problem and it isn't working out, so i think i'm either making a dumb mistake or misunderstanding what it's asking. A particle moves along the x axis so that its velocity at any time t greater than or equal to 0 is given … 
Trigonometry
4. Find the exact value for sin(x+y) if sinx=4/5 and cos y = 15/17. Angles x and y are in the fourth quadrant. 5. Find the exact value for cos 165degrees using the halfangle identity. 1. Solve: 2 cos^2x  3 cosx + 1 = 0 for 0 less … 
Trigonometry
I really need help with this trigonometry question.please any help is appreciated. 1.I have to draw the graph of y=cos x from 0deg to 360deg. 2.Be sure to show a table of vales similar to the this table. colum X l colum :y=sinx 0 l … 
Trigonometry
a. Find the exact value of sin (theta  pi/6) b. Find the exact value of cos (theta  pi/4) c. For what numbers x, 2pi less than or equal to x less than or equal to 2pi does cos x = 1 d. What is the range of the cosine function? 
Trigonometry
Solve the equation sin^2xcos^2x=0 over the interval [0, 2pi). Having trouble getting started. 
Trigonometry
Solve each equation on the interval [0, 2pi): a. 4sin^2(x)3=0 b. cos(3x)=1 
Calculus help??
I'm not sure how to solve this and help would be great! d/dx [definite integral from 0 to x of (2pi*u) du] is: a. 0 b. 1/2pi sin x c. sin(2pi x) d. cos (2pi x) e. 2pi cos (2pi x) This is the fundamental theorem, right? 
Trigonometry
Use De Moivre's Theorem to write the complex number in trigonometric form (cos(2pi)/7)+ i sin((2pi)/7))^5 
trigonometry
Solve the equation in the interval [0, 2pi]. 2sin(t)cos(t)cos(t)+2sin(t)1=0 Answer needs to be formatted as x={Insert answers here}pi If the answer is something like pi/6 it simply goes in as 1/6th since pi is already given at the … 
Algebra 2
Find the values of the inverse function in radians. sin^1(0.65) a. 0.71+2pi n and 0.71+2pi n b. 0.71+2pi n and 3.85+2pi n c. 0.86+2pi n and 0.86 +2pi n d. 0.61+2pi n and 2.54+2pi n 2. tan^1(0.09) a.0.09+2pi n b. no such angle …