posted by Anonymous .
A ball of mass .15 kg and a radius of .24 m is at the top of a 3.5 m tall hill with a 25 degree incline. What is the velocity of the ball as it reaches the bottom of the hill if it (a) rolls without slipping? (b)slips without rolling?
The height of the hill H tells you the potential energy per unit mass, gH.
This equals the kinetic energy at the bottom in both cases.
In case (b), the KE per unit mass is just V squared.
In acase (a), rotational kinetic energy must be included, and the velocity will be less.
You will need to use the equation for the moment of inertia of a sphere.
We wll be happy to critique your work.
Ok thanks! I think I figured out the equation..
you use mgh=1/2mv^2 + 1/2Iw^2 and solve for v. right?