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find the points to the curve
y=(cos x)/ (2 + sin x)
at which the tangent is horizontal...
can you explain how get the answer thoroughly and step by step...

  • math -

    using the quotient rule,
    dydx = [(2+sinx)(-sinx) - cosx(cosx)]/(2+sinx)^2

    a horizontal tangent implies the slope is zero, that is, the derivative is zero.
    (2+sinx)(-sinx) - cosx(cosx) = 0
    -2sinx - sin^2x - cos^2x = 0
    -2sinx - (sin^2x + cos^2x) = 0
    -2sinx - 1 = 0
    sinx = -1/2
    x = 7π/6 or x = 11π/6 ..... (210° or 330°)
    sub 7π/6 and 11π/6 into the original equation to find the corresponding y values.

    Those will give you the points in the domain 0 ≤ x ≤ 2π

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