college
posted by saad .
3x2+x+1=0

since it's not factorable, we use quadratic formula:
x = [b + sqrt(b^2 4ac)]/(2a)
where a=3, b=1, and c=1
substituting:
x = [1 + sqrt(1^2  4*3*1)]/(2*3)
x = [1 + sqrt(11)]/6
thus
x = [1 + i*sqrt(11)]/6 ; and
x = [1  i*sqrt(11)]/6
*note: i = sqrt(1)
hope this helps~ 
oops, some typo:
x = [1 + i*sqrt(11)]/6 ; and
x = [1  i*sqrt(11)]/6