Calculus 1
posted by Ivan .
Calculate f'(1)
f(x) = x^7 * h(x)
h(1) = 5
h'(1) = 8
Answer is 27, but I got no idea how to get there.

first, recall chain rule, since there there is a function of x multiplied by another function of x (that is, x^7 and h(x)),, given a function f(x)=g(x)*h(x)
f'(x) = g'(x)*h(x) + g(x)*h'(x)
therefore, to get derivative of f(x)=x^7 *h(x), first get the derivative of x^7 multiplied by h(x) plus the derivative of h(x) [which is h'(x)] multiplied by x^7,,
since it is evaluated at 1, substitute values for h(1) and h'(1), which is given in the problem,,
so there,, please ask questions if there's something you did not understand,, :) 
find f' (x) first of all using the product rule assuming we are differentiating with respect to x
f' (x) = x^7 (h' (x)) + 7x^6 (h(x))
so f'1) = (1)^7 (h'(1)) + 7(1)^6 (h(1))
= 1(5) + 7(1)^6 (8)
=5 + 56
= 51
I don't see how they got 27 
I see my error, I substituted the wrong way, should have been ...
so f'1) = (1)^7 (h'(1)) + 7(1)^6 (h(1))
= 1(8) + 7(1)^6 (5)
= 8 + 35
= 27