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What volume of 0.0482 M Ba(OH)2 is required to neutralize exactly 16.10 mL of 0.141 M H3PO4? Phosphoric acid contains three acidic hydrogens.

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    Write the equation and balance it.
    3Ba(OH)2 + 2H3PO4 ==> Ba3(PO4)2 + 6H2O

    moles H3PO4 given = M x L = ??
    Using the coefficients in the balancd equation, convert moles H3PO4 to moles Ba(OH)2.

    Now M Ba(OH)2 = moles Ba(OH)2/L Ba(OH)2.
    You have M and moles, solve for L.

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