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a cylinder has a radius of 3cm and a length of 10cm every dimention of the cylinder is multiplied by 3 to form a new cylinder how is the ratio of the volumes related the ratio of corresponding dimensions? how would i do this?

• Math 8th grade algerbra -

Volume of cylinder = area of the base * height , or
V = pi*(r^2)*h
V,original = pi*(3^2)(10)
*you solve for this.

then for the new one,
r,new = 3*3 = 9
h,new = 3*10 = 30
V, new = pi*(9^2)(30)
you solve also for this.

then compare their volumes, find:
(V,new)/V

so there,, hope this helps~ :)

• Math 8th grade algerbra -

Thank you

• Math 8th grade algerbra -

• Math 8th grade algerbra -

yes,, (V,new)/V = 27,,
and ration of dimensions is 3 (because it is tripled according to problem)

now, how is 27 related to 3?

• Math 8th grade pre algerbra -

Y=5x;(15, -3)

• Math 8th grade algerbra -

How is the ratio of the volumes related to the ratio of corresponding dimensions?

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