math!!!!!!! help 3
posted by niki .
a water cooler contains 5 gallons of water.if drink 3/5 gallon for each of the next 6 days how many gallons will be left in water cooler at the end of the sixth?

5(3/5*6)

is it 3 3/5

3 3/5 was the part in parenthesis. So now do 53 3/5.

Jen told you to subtract. You didn't do that.

first multiply 3/5 by 6
3/5 * 6 = 18/5
then convert 5 into fraction such that its denominator is 5:
5 = 25/5
therefore:
(2518)/5 = 7/5 or 1 2/5 gallons
so there,, :) 
Jai, please allow the students a chance to attempt the problems on their own with our guidance.

i have a question for jen

Yes?

oh sorry.
alright, Jen. 
well i got stuck because i did 3/5*6/1 and i got 18/5 then i did 18 divied by 5 and got 3 3/5 so is 3 3/5 the answer

3 3/5 gallons is how much water you drank after 6 days. 6 days * 3/5 gallons each day is 3 3/5. BUT..the question is how much water is left. If you started with 5 gallons, now you must do 53 3/5 for your answer.

ok so the answer would then be 1 2/5s gallons?

Yes! Good job, Niki!

THANK YOU 4 helping math isent my strong suit but it helps to be walked through it instead of just given the answer i greatly appretiate your time

that did not help me

en 100 platos cuantos litros de agua dentra

You first need to find out how many gallons would be drank after 6 days, so you multiply 3/5 * 6 to get 18/5. Then you subtract 18/5 from the original 5 gallons so 5  18/5. You have to make equivalent fractions so you put the 5 over one, and multiply the numerator and denominator by the same thing so 5*5 and 1*5. This give you a new fraction of 25/5, which was the original amount of 5 gallons. Then you subtract the original amount from the amount drank after 6 days, so 25/5  18/5= 7/5. Then you make the improper fraction into a mixed number, divide 7 by 5 to get 2 1/5 gallons.

Start: 5 gallons of water
Drank: 3/5 each day for 6 days, or 3/5 x
6/1=18/5
Subtract what was drank from the 5 gallons
2 ways to do this:
IMPROPER FRACTION:
5/1 minus 18/5=25/518/5=7/5 or 1 2/5
MIXED FRACTION WHERE WHOLE NUMBER IS RENAMED:
5 minus 3 3/5 = 4 5/5  3 3/5 = 1 2/5
Started with 5 gallons, drank 3 3/5 gallons, so 1 2/5 gallons was left at the end of 6 days. 
Start: 5 gallons of water
Drank: 3/5 each day for 6 days, or 3/5 x
6/1=18/5
Subtract what was drank from the 5 gallons
2 ways to do this:
IMPROPER FRACTION:
5/1 minus 18/5=25/518/5=7/5 or 1 2/5
MIXED FRACTION WHERE WHOLE NUMBER IS RENAMED:
5 minus 3 3/5 = 4 5/5  3 3/5 = 1 2/5
Started with 5 gallons, drank 3 3/5 gallons, so 1 2/5 gallons was left at the end of 6 days.
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