How many liters of a 0.530M sucrose (C12H22O11) solution contain 1.3kg of sucrose?
To find the number of liters of a sucrose solution containing 1.3kg of sucrose, we need to use the formula:
moles = mass / molar mass
First, let's calculate the molar mass of sucrose (C12H22O11):
Molar mass (C) = 12.01 g/mol
Molar mass (H) = 1.008 g/mol
Molar mass (O) = 16.00 g/mol
Molar mass (C12H22O11) = (12.01 * 12) + (1.008 * 22) + (16.00 * 11) = 342.34 g/mol
Next, let's calculate the number of moles of sucrose in 1.3kg:
moles = mass / molar mass = 1300g / 342.34 g/mol ≈ 3.799 moles
Now, let's calculate the volume of the solution in liters:
Molarity (M) = 0.530 M
Volume (V) = moles / Molarity = 3.799 moles / 0.530 M ≈ 7.163 L
Therefore, approximately 7.163 liters of a 0.530M sucrose solution contain 1.3kg of sucrose.
To find the number of liters of a 0.530M sucrose solution that contains 1.3kg of sucrose, we need to use the formula:
Molarity (M) = moles of solute / volume of solution in liters.
First, we need to calculate the moles of sucrose using the given mass:
Mass of sucrose = 1.3kg = 1300g
Now, we can calculate the number of moles of sucrose:
Moles of sucrose = Mass of sucrose / molar mass of sucrose
The molar mass of sucrose (C12H22O11) can be calculated using the atomic masses:
(12g/mol * 12) + (1g/mol * 22) + (16g/mol * 11) = 342g/mol
Moles of sucrose = 1300g / 342g/mol
Now that we have the moles of sucrose, we can use the formula to find the volume of the solution in liters:
Molarity (M) = Moles of sucrose / Volume of solution
0.530M = Moles of sucrose / Volume of solution
Rearranging the formula, we can solve for the volume of the solution:
Volume of solution = Moles of sucrose / Molarity (M)
Substituting in the known values:
Volume of solution = (1300g / 342g/mol) / 0.530M
Volume of solution = 0.9568 mol / 0.530M
Now, we can calculate the volume of the solution in liters:
Volume of solution = 0.9568 mol / 0.530 mol/L
Volume of solution = 1.805 L
Therefore, 1.3kg of sucrose dissolved in a 0.530M sucrose solution would have a volume of 1.805 liters.
Convert 1.3 kg to grams, then to moles. moles = grams/molar mass.
Now that you know how many moles you need, use M = moles/L. You know moles and M, solve for L.