chemistry

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A reaction starts with 1.00 mol each of PCl3 and Cl2 in a 1.00-L flask. When equilibrium is established at 250 degree Celsius in the reaction PCl3(g)+ Cl2(g)--> PCl5(g), the amount of PCl5 present is 0.82 mol. What is Kc for this reaction?

  • chemistry -

    PCl3 + Cl2 ==> PCl5.

    initial:
    PCl3 = 1 mole/1 L = 1 M
    Cl2 = 1 M
    PCl5 = 0

    change:
    PCl5 = +x
    Cl2 = -x
    PCl3 = -x

    equilibrium:
    PCl3 = 1-x
    Cl2 = 1-x
    PCl5 = x = 0.82M
    Redo PCl3 = 1-x = 1-0.82 = ??
    Redo Cl2 = 1-x = 1 - 0.82 = ??

    Substitute the equilibrium values into Kc and solve for Keq.

  • chemistry -

    keq is 1.53 and the Kc isproducts over reactants

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