College Algebra
posted by Lee .
I could not figure out the answer to this Problem:
The quadratic function
f(x)= 2x^2 =4x +3 can be used to solve the following inequality:
2x^2 4x < 3
First use the Quadratic Formula to find the xintercept of f.
This problem asks that the answer be separated by commas and rounded to nearest tenth
Also solution set is requested and put in interval notation and numbers rounded to nearest tenth
My answers to this problem where incorrect The xintercepts I found were 2.4,5.8
and the solution set I had is: (infinity, 2.4] union [5.8,infinity)

solving the quadratic
2x^2  4x + 3 = 0 or
2x^2 + 4x  3 = 0 yields
x = (4 ± √40)/4
x = .58 or 2.58 not your answers.
so x < 2.58 OR x > .58
round off and express in the form they want. 
So once I have to convert sqrt of 40 and solve from there?

Thank you so much for your help.