trig
posted by Anonymous .
how do i find six trig functions for cos(pi over 2x)=3/5, cos x=4/5?

given cos x = 4/5
by making a diagram, you should recognize the 3,4,5 rightangles triangle
secondly, the cosine is positive in quadrants I and IV
in I:
sinx = 3/5 , csc x = 5/3
cosx = 4/5 , sec x = 5/4
tanx = 4/3 , cot x = 3/4
you do IV
back to cos(pi over 2x)=3/5
cos (π/2  x) = 3/5
(cosπ/2)(cosx) + (sinπ/2)(sinx)= 3/5
sinx = 3/5
(hey, we knew that!)
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