# algebra

posted by .

Find two consecutive even integers such that the sum of the larger and twice the smaller is 62. PLEASE HELP I DON'T GET IT!/:

• algebra -

let n = smaller, then since they are "consecutive even integers", n + 2 = larger.

(n + 2) + 2n = 62

Solve for n.

• algebra -

n=20

## Similar Questions

1. ### Math

The greater of two consecutive even integers is six less than twice the smaller. Find the integers. Let the smaller be x. That means that the larger is x+2. From your statement x+2=2x-6 Solve for x. I hope this helps. Thanks for asking.
2. ### algebra

the larger of two consecutive integers is 7 greater than twice the smaller. find the intergers
3. ### Algebra 1

The larger of two consecutive integers is 7 greater than twice the smaller. Find the integers. A) 4,5 B) -8,-9 C) -5,-6
4. ### math

Find two consecutive even integers such that the square of the smaller is 10 more than the larger.
5. ### Math

The smaller of two consecutive even integers is 2 more than twice the larger. Find the numbers.
6. ### Math

Find two consecutive odd integers such that the sum of four times the larger and twice the smaller is 194. Please help! Thank you!
7. ### Math

Find two consecutive odd integers such that the sum of four times the larger and twice the smaller is 194. Help Thank you!
8. ### Math

Find two consecutive even integers such that the sum of the larger and 3 times the smaller is 234. I don't get how to put it as in equation.
9. ### Algebra

For two consecutive positive even integers, the product of the smaller and twice the larger is 160. Find the integers.
10. ### Algebra

The difference of two integers is 6. The sum of twice the smaller and the larger is 72. Find the integers. The sum of 3 times a larger integer and 2 my answer the lager integer is 192 and the smaller integer is 72

More Similar Questions