algebra
posted by john .
the length of a rectangular jewlery box is 6 inches more than twice the width. the perimeter is 36 inches. find the length and width?

L=2W+6
Perimeeter=2W+2L=2*(W+L)=2*(W+2W+6) =2*(3W+6)=6W+12
Perimeter is 36 inches
6W+12=36 , 6w=3612=24 Divided with 6
W=(24/6)=4 W=4
L=2W+6=2*4+6=8+6=14 L=14
Perimeter 2*(L+W)=2*(4+14)= 2*18= 36in