chemistry
posted by april .
A 16.5 cm3 bubble under the ocean at 2.1 atm and 12.5oC surfaces to 1.0 atm and 22.1oC. What is the new volume (in cm3)?
i used (p1)(V1)/T1=(P2)(V2)/T2
(2.1)(.0165)/285.65=(1)(V2)/295.25
THE ANSWER I GOT IS .0335
i changed 16.5 to liters which is why its .0165

I get close to 0.0335 (in cc).
2.1*16.5*295.25/285.65 = 35.81 cc. I think you have
a) punched in a wrong digit somewhere or
b)rounded the answer in parts before going to the next multiplication/division.
I keep all of the numbers in the calculator until the final number is read.
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