# CHEMISTRY- boiling point

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0.1m aqueous solution of HCl and 0.1m aqueous solution of C6H12O6.
calculate the boiling point of each

i know the eq. dTb=Kbm
but i have no temperatures. this is the question

• CHEMISTRY- boiling point -

It is an aqueous solution. You know that the boiling point with no HCl is 100 C. Use Kb and the molarity to compute the change in B.P.

• CHEMISTRY- boiling point -

can you show me. i'm confused.

• CHEMISTRY- boiling point -

delta T = i*Kb*molality
i is the van't Hoff factor, which for HCl is 2 (it dissolves into two particles).
delta T = 2*0.512*0.1 = 0.102
Therefore, the new boiling point for water must be 100 C + 0.102 = ??

For the sugar solution,
i = 1 since it doesn't ionize.
delta T = i*Kb*m
delta T = 1*0.512*0.1 = 0.0512
New boiling point will be
100 C + 0.0512.
The problem is hoping you will see the difference between the two; i.e., the HCl ionizes to give two particles and has just twice the effect as the other one although the molality is the same.

• CHEMISTRY- boiling point -

is the Kb 0.51 just standard BP of water? i think that's where i'm getting lost.

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