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The drawing shows a version of the loop-the-loop trick for a small car. If the car is given an initial speed of 4.5 m/s, what is the largest value that the radius r can have if the car is to remain in contact with the circular track at all times?

  • physics -

    There is no drawing.
    Require that the centripetal force at the top of the loop be equal to M g. Solve for the r that satisfies that requirement, with V determined by conservation of energy.

  • physics -

    but you don't know hf or ho, how do you you use the conservation of energy equation?

  • physics -

    This is what I found....
    When the car is at the top of the track the centripetal
    force consists of the full weight of the car.

    mv2/r = mg

    Applying the conservation of energy between the bottom and the top of the track gives

    (1/2)mv^2 + mg(2r) = (1/2)mv0^2

    Using both of the above equations

    v0^2 = 5gr

    so

    r = v0^2/(5g) = (4.5 m/s)^2/(49.0m/s^2) =

    Hope that helps

  • physics -

    jhhhhhhhhhhhbm

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