posted by Anonymous .
my number is a multiple of 5, but doesnt end in 5, the prime factorization of my number is a string three numbers, two of the numbers in the prime factorization are the same, my number is bigger than the seventh square number
It's bigger than 49, and it must be a multiple of 10 (since it doesn't end in a 5)..so your choices are 50, 60, 70, 80, 90, etc..Now check your other conditions and find your number.
could it be 20? it does not end in 5, the factor string is 2 * 2 * 5, I'm not sure about the last part though - the number being bigger than the seventh square number... just a thought - double check with someone else though.
the 7th square number is 49, so it has to bigger than 49
must end in 0
factors: two the same, third diffferent
50 = 5x5x2
The 7th square number is 49, so it has to be bigger than that.
what is the answer????