math
posted by Anonymous .
my number is a multiple of 5, but doesnt end in 5, the prime factorization of my number is a string three numbers, two of the numbers in the prime factorization are the same, my number is bigger than the seventh square number

It's bigger than 49, and it must be a multiple of 10 (since it doesn't end in a 5)..so your choices are 50, 60, 70, 80, 90, etc..Now check your other conditions and find your number.

could it be 20? it does not end in 5, the factor string is 2 * 2 * 5, I'm not sure about the last part though  the number being bigger than the seventh square number... just a thought  double check with someone else though.

the 7th square number is 49, so it has to bigger than 49
must end in 0
factors: two the same, third diffferent
50 = 5x5x2
mmmhhh? 
The 7th square number is 49, so it has to be bigger than that.

50!!

what is the answer????

50

The answer is 50!!!!!!!

We know the number of the multiple of five so that takes out all the numbers that end in five. The next step is to find the prime factorization of all the numbers up to 50. So now that leaves us with couple numbers. So now what will you do is see what number has two numbers that are the same in the prime factorization. That leaves us with still a couple members. No the seventh number is squared and that if 49 in the number 50 so that means that it has to be 50 because 55 is to high and 45 is to low and they both have five in then so the only answer is 50!!!!!!! WE SLOVED THE PROBLEM!!!!!!!!!!!!$$$$$$$$!!!!!!!!!$$$$$$$!!!!!!!

its 50 asses
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