posted by Hannah .
Write an equation of the line satisfying the given condition.
a) x intercept = 3 y intercept=-2
I am really not sure how to start here.
b) vertical line containing (5,-1)
Would it be y=5x-1?
c) parallel to the line 3x-4y=5 and containing the points (3,-6) .
I know that the line has to have the same slope as the one about.
d) Find the slope and y intercept of the line 4x-6y=-3
To find the y value would i plug in zero for the x and solve? And then I can find the slope?
a) isn't the information like being given two points?
So just find the slope and you know the y-intercept, so
y = mx -2
b) a vertical slope has an undefined slope
It's equation will simply be x = ? (whatever the x of the given point is)
So x = 5
c) real easy
since it has the same slope the new equation must also start with
3x - 4y = k, where k is the only number that will differ.
sub in your given point to find k, and you are done
d) rearrange 4x - 6y = -3 to the form y= mx + b
-6y = -4x - 3
divide by -6
y = (-4/-6)x -3/-6
y = (2/3)x + 1/2