Algebra
posted by John .
I4x4I=8x+16 (The 2 "I" are absolute signs)

[4x  4] = 8x + 16.
There are 2 possible solutions:
4x  4 = + (8x + 16),
First Eq:
4x  4 = +(8x + 16),
4x  8x = 16 + 4,
4x = 20,
x = 5.
2nd Eq:
4x  4 = (8x + 16),
4x  4 = 8x  16,
4x + 8x = 16 + 4,
12x = 12,
x = 1.
Check 1st Eq:
[4*5 4] = 8*5 + 16,
[24] = 24.
The above statement is NOT true:
[24] = +24.
Therefore, 5 is NOT a solution.
Check 2nd Eq:
[4*1  4] = 8*1 + 16,
[8] = 8. TRUE.
Solution:x = 1.
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